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Old May 15th, 2002, 04:16 AM
krinid krinid is offline
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How can I GROUP by MONTH using a date variable?

How do I group by MONTH in a query using a DATE variable?

I want to count the number of entries in a table based on # of events per month.

If I use the following code, it groups by DAY (using the entire date) and thus I get # of events per DAY:

SELECT WORK.Date, Count(WORK.Event)
FROM WORK
GROUP BY WORK.Date, WORK.Event;

Since I'm using Access, I can implement the following code:

SELECT WORK.Event, Format(WORK.Date, "yy/mm") AS [Month], Count(Event)
FROM [WORK]
GROUP BY WORK.Event, Format(WORK.Date, "yy/mm");

But this is executable ONLY on Access, and I'd rather implement a pure SQL solution, not using the VB function 'Format' if possible, and I'm sure there must be a way.

Can anyone help?

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Old May 20th, 2002, 04:15 PM
tudor tudor is offline
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RE: How can I GROUP by MONTH using a date variable?


Quote:
How do I group by MONTH in a query using a DATE variable?

I want to count the number of entries in a table based on # of events per month.

If I use the following code, it groups by DAY (using the entire date) and thus I get # of events per DAY:

SELECT WORK.Date, Count(WORK.Event)
FROM WORK
GROUP BY WORK.Date, WORK.Event;

Since I'm using Access, I can implement the following code:

SELECT WORK.Event, Format(WORK.Date, "yy/mm") AS [Month], Count(Event)
FROM [WORK]
GROUP BY WORK.Event, Format(WORK.Date, "yy/mm");

But this is executable ONLY on Access, and I'd rather implement a pure SQL solution, not using the VB function 'Format' if possible, and I'm sure there must be a way.

Can anyone help?


Try to use YEAR and MONTH SQL function
(e.g.

SELECT work.event, year(work.date) as year, month(work.date) as month, count(work.event) as noofevents from work group by work.event, year, month
)

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  #3  
Old May 20th, 2002, 11:22 PM
sLYsHARk sLYsHARk is offline
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RE: How can I GROUP by MONTH using a date variable?

try this:

SELECT * FROM WORK
WHERE (((Year(Date))=2002) AND ((Month(DATE))=11));

This should help you to solve the problem...

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