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  #1  
Old November 14th, 2002, 09:32 PM
daeken daeken is offline
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algorithm
With my algorithm, I was able to get (number_of_discs_in_stack - 1) moves as the maximum number of moves for ANY stack... anyone able to beat this?
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  #2  
Old November 14th, 2002, 10:39 PM
webhappy webhappy is offline
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RE: algorithm
Maybe it isn't as impossible as I thought...

Only a little more than a week left... hm...
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  #3  
Old November 14th, 2002, 10:55 PM
notepad notepad is offline
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RE: algorithm
Quote:
I was able to get (number_of_discs_in_stack - 1) moves as the maximum number of moves for ANY stack

4-2-3-1
1-3-2-2
3-1-1-3
2-4-4-4

four discs, can you get minus one with that one? i wanna see a visual plzkthx
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  #4  
Old November 14th, 2002, 11:30 PM
Matt Matt is offline
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RE: algorithm
4-2-3-1
1-3-2-2
3-1-1-3
2-4-4-4

what you just posted is n-1 ....

original:
4
1
3
2

after first flip:
2
3
1
4

after second flip:
3
2
1
4

after third flip:
1
2
3
4
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  #5  
Old November 14th, 2002, 11:33 PM
notepad notepad is offline
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RE: algorithm
doh! alright leave me alone
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  #6  
Old November 14th, 2002, 11:54 PM
diclophis diclophis is offline
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RE: algorithm
5
3
6
1
4
2

how many does this take?
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  #7  
Old November 15th, 2002, 01:22 AM
daeken daeken is offline
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RE: RE: algorithm
5-5-1-1-1
3-3-4-3-2
6-2-2-2-3
1-4-3-4-4
4-1-5-5-5
2-6-6-6-6

n-1

-edit-

I just realized how badly I don't follow the rules
code pending fixing....
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  #8  
Old November 15th, 2002, 03:43 AM
diclophis diclophis is offline
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RE: algorithm
haha, it looks liek your flipping from both sides of the stack...
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  #9  
Old November 15th, 2002, 03:46 AM
webhappy webhappy is offline
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RE: RE: RE: algorithm
Quote:
5-5-1-1-1
3-3-4-3-2
6-2-2-2-3
1-4-3-4-4
4-1-5-5-5
2-6-6-6-6


On the 3rd flip, looks like he's flipping a middle of it ?
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  #10  
Old November 15th, 2002, 09:59 PM
-vertigo- -vertigo- is offline
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RE: algorithm
Interestingly enough, after looking at those numbers of yours, diclophis, I notice my algorith needed some adjustment. It took 8 steps, whereas I see now it can easily get 7.

Another interesting set of numbers are:
6, 3, 7, 9, 2, 4, 1, 8, 5.

I've got ten flips on that one.

I think the winner of this comp should be eligable for the Nobel Prize for Algorithmic Development (if only).
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  #11  
Old November 16th, 2002, 12:24 PM
TCR TCR is offline
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RE: algorithm
=>> -vertigo-
I also got 10 moves it your number combination... dont think i can get it lower.... Hard work... but still...
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Old November 16th, 2002, 01:59 PM
TCR TCR is offline
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RE: algorithm
Hmmm.... i looks like i have a kind of error...
with your numbers i have ten moves... but but...
when I output every move, I looks like i make moves, that just move itself
Well.. basicly i really have 7 moves then... Let fix the bugs ;)

BTW Matt... im really not interested in making a nice output... I very hard.
Is it okay every step just shown with etc..

3-2-1
1-2-3

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  #13  
Old November 16th, 2002, 02:15 PM
Matt Matt is offline
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RE: algorithm
You can display it any way you choose...
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Old November 16th, 2002, 02:45 PM
TCR TCR is offline
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RE: algorithm
Matt,
Just one thing more...
What error level do you set? You do not write anything about that this time?
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  #15  
Old November 16th, 2002, 05:04 PM
Matt Matt is offline
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RE: algorithm
error_reporting = E_ALL & ~E_NOTICE
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