Functions, return?

function pass_check($username, $password)
{
$sql = "SELECT password FROM user_info WHERE username='". $username . "'";
$result = mysql_query($sql);
$real_password = mysql_fetch_array($result);
if ($password == $real_password)
{
return 1;
} else {
return 0;
}
}

//Should not this call the function and give the $passcheck the value 1 or 0

$passcheck = pass_check($username, $password);

It should...

NO! it shouldn't!

look at the php man for the explanation on what does mysql_fetch_row() function do:

http://php.net/mysql_fetch_array

when u read that, u should know that all u need to change is the condition in the if statement to:

It would return 0 because of the else...

function pass_check($username, $password)
{
$sql = "SELECT password FROM user_info WHERE username='". $username . "'";
$result = mysql_query($sql);
$real_password = mysql_fetch_array($result);
if ($password == $real_password[0])
{
return 1;
} else {
return 0;
}
}

This code works, thanks zombie. As you see Im a newbie. Besides, I guess I should learn about session handeling.

To you other 'Anonymous', the function ends if $password = $real_password[0]
The [0] means the first row in the array, $real_password turns into an array when I use mysql_fetch_array

Correct me if Im far of track

NO! it doesn't mean first row of the array, it means first element of the array, or in this case, first column in the row.

and NO, mysql_fetch_array DOESN'T turn anything into an array, it returns array of all columns in one table row!

you should read more about http://php.net/mysql and not about sessions...