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  #1  
Old August 13th, 2002, 02:59 PM
straw straw is offline
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mysql_fetch Problem

Hi!
Please can some one help me with this problem. I have fetches on an other site and that one is OK. Im new programming with PHP so I dont understand whats the problem.

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/p/pocketli/www/mobile/search/search.php on line 29

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/p/pocketli/www/mobile/search/search.php on line 45

Do you know whats wrang?
Here is the new code:

<?
if ($searchstring)
{
if (!isset($start)) $start = 0;
include("common.php");
$link = dbConnect();
$query ="SELECT kundid, icon, namn, typ FROM $table WHERE namn LIKE '%$searchstring%' LIMIT" . $start . ", 10";
$result = mysql_query($query);

?>
<br>
<table border="0" width="200" cellpadding="0" cellspacing="0">

<?
while ($raden = mysql_fetch_row($result)){
echo "<tr bgcolor=#cccccc>
<td width=20><img src='$raden[1]' width=20 height=20></td>
<td><font face=verdana size=2>&nbsp;<b><a href=info.php?kundid=$raden[0]>$raden[2]</a></b></font></td>
<td><font face=verdana size=1>$raden[3]</font></td>
</tr>
<tr height=2 bgcolor=#ffffff>
<td colspan=3>&nbsp;</td>
</tr>";
}

?>
<tr><td colspan=3>
<?
$query = "SELECT count(*) as count FROM table";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
$numrows = $row['count'];
if($start > 0)
echo "<a href="" . $PHP_SELF . "?start=" . ($start - 10) . "">Previous</a><BR>n";
if($numrows > ($start + 10))
echo "<a href="" . $PHP_SELF . "?start=" . ($start + 10) . "">Next</a><BR>n";

?>
</td></tr>
</table>
<?
} mysql_close($link);
?>


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  #2  
Old August 14th, 2002, 03:34 AM
siteworkspro.com siteworkspro.com is offline
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RE: mysql_fetch Problem

The error is caused by something wrong with your SQL query.

try this
$query ="SELECT * FROM $table WHERE namn LIKE '%$searchstring%' LIMIT $start , 10";


if thats still causing problems, use this


$result = mysql_query($query) or die(mysql_error);


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  #3  
Old August 14th, 2002, 04:11 AM
D1NGO D1NGO is offline
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RE: mysql_fetch Problem

you should actually use

$result = mysql_query($query) or die(mysql_error());

instead of

$result = mysql_query($query) or die(mysql_error);


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  #4  
Old August 14th, 2002, 11:12 AM
straw straw is offline
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RE: mysql_fetch Problem

Thanks! Now is the fetch Problem not a Problem any more.
But I still dont get any new rows when I click on the next link.
Any suggestion.

//Micke

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