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On-Line Catalog

Discuss On-Line Catalog in the PHP Coding forum on Codewalkers.
On-Line Catalog Having problems with a PHP script you are coding? This is the place to get help!

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  #1  
Old May 21st, 2002, 08:52 PM
Anonymous Anonymous is offline
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On-Line Catalog
Ok, got a question for the whizkids here. I have created a PHP page that reads a MySQL DB. It then produces a page of products, with images, descriptions and price. I have broken it down by catagory so only the right pieces land on their designated pages. However all said and done, I have 50 pieces on one page. How can I cut it off at say 10, and clicking "Continue" produces another page of 10.???
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  #2  
Old May 21st, 2002, 09:01 PM
Matt Matt is offline
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RE: On-Line Catalog
Check out this tutorial on previous and next links:

http://codewalkers.com/tutorials.php?show=4
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  #3  
Old May 21st, 2002, 10:08 PM
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RE: On-Line Catalog
Thanks a lot!!! I'm fairly new to this, and like it a lot. That was the fastest most helpful come back I've ever gotten. Thanks again,

Dean
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Old May 22nd, 2002, 08:43 PM
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RE: On-Line Catalog
Ok most of it seems to be working... some trial and error, which makes me learn. However, as a test I put an echo $start at the end of your design, and it equaled zero. Where in the code does $start get set to 10, or another value? Also the url generated by $start+10 is
?start=0+10. Is that right? or is it supposed to be getting the value of that which is just 10? Again any help would be great...


Dean
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Old May 22nd, 2002, 09:17 PM
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RE: On-Line Catalog
i'm not sure if this is what you're talking about.. but try adding something like the following..

php Code:
Original - php Code 
  1.  
  2. if($start <= 0)
  3. {
  4.     $start = 1;
  5. }


is that what you're having a problem with?
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Old May 22nd, 2002, 09:22 PM
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RE: On-Line Catalog
the url should be getting the value of that which would be 10...
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Old May 22nd, 2002, 09:32 PM
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RE: On-Line Catalog
sorry i don't think i understand the question.
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Old May 22nd, 2002, 09:35 PM
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RE: On-Line Catalog
if($numrows>($start+10)) $display_footer .= "<a href="$PHP_SELF?start=$start+=10">Next</a> $start" ;

Generates...

<a href="/hollywood.php3?start=0+=10">Next</a> 0

I've tried adding quotes, escaping characters... I'm at a loss. The final $start in my code is to test the value, which came up as you can see, after the link code as a zero.

How do I force it to add the $start and the 10?

Again all help is appreciated,

Dean
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  #9  
Old May 22nd, 2002, 09:47 PM
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RE: On-Line Catalog
how about..

php Code:
Original - php Code 
  1.  
  2. if($numrows>($start+10))
  3. {
  4.     $start += 10;
  5.     $display_footer .= "<a href="$PHP_SELF?start=$start">Next</a> $start";
  6. }


????
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  #10  
Old May 22nd, 2002, 09:59 PM
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RE: On-Line Catalog
or even...

if($numrows>($start+10)) $display_footer .= "<a href="$PHP_SELF?start=" . $start+=10; . "">Next</a> $start";

hmm..
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