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#1
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parameter transfer in php script
I tried the following way to call another php script:
include "http://.../script1.php?password='i'"; the script1.php is loaded successfully but the parameter "i" is not passed. Does anyone know the reason? thanks |
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#2
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RE: parameter transfer in php script
& is signifigant in passing data. What is the password suppose to equal?
password=pswd then script1.php will recv password set to pswd. |
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#3
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RE: parameter transfer in php script
there is a easier way to pass a variable then that
$password = "'i'";"; include "http://.../script1.php"; |
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#4
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RE: parameter transfer in php script
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| Viewing: Codewalkers Forums > PHP Related > PHP Coding > parameter transfer in php script |
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