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  #1  
Old September 23rd, 2009, 01:45 AM
anitha anitha is offline
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Thumbs up php5 - PHP Coding

How to create Menus in php

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Old September 23rd, 2009, 08:28 AM
MatthewJ MatthewJ is offline
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More information is going to be needed to help, but I would start by going to Google and typing "creating menus with php"

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Old September 23rd, 2009, 05:39 PM
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icandothat icandothat is offline
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I use this
PHP Code:
function makeMenue($ODbo,$menue,$selected=''){
/***********************************************
* function:makeMenue
* Arguments: (obj)$ODbo, (str) menue, (str)selected menue item
* returns: html formated unordered list
* purpose: determine based on user, and meue what menue items a person can see
* Special Case: none
************************************************/
    
$user_roles $_SESSION['Ouser']->user_roles;
    
    
//determine what menue to make
    
$menue_id getMenueId($ODbo,$menue);    
    
    
//determine which of these entries these roles can see.
    
$result determineViewableEntries($ODbo,  $menue_id,$user_roles);
    if(
$result == -1){
        return 
'';
    }
    
//this should get entry id's where the user's role is appropriate
    
$output buildMenue($ODbo,$result,$selected);
    
    return 
$output;



PHP Code:
function buildMenue($ODbo,$result,$selected=''){
//echo $selected."";//debug
    
$output '';
    foreach(
$result as $entry_id){
    
        
//$entry_id = $row['MENUE_ENTRY_ID']; 
        
$sql "select * from menue_entries    where id = $entry_id";
        
$entry_result $ODbo->executeQuery($sql,'','ASSOC',0);
        
        foreach(
$entry_result as $entry_row){
            
            
            if(
$entry_row['DISPLAY_NAME'] == $selected){
                
$output .= "\n<li id=\"current\" ";
            }else{
                
$output .= "\n<li id=\"$entry_row[DISPLAY_NAME]\"";
            }
            
$output .= " class=\"$entry_row[DISPLAY_NAME]\">\n";
            
/*
                I'm looking for a non cheezy workaround here
                but I want an alternative that will allow me to embed js
                into the LINK vs a real link
                I think I'll use a key like JS or # to indicate that the follow 
                is  js and should not be treated like a link.
                TODO: disembed array references below.
            */
            
if(substr($entry_row['LINK'],0,1) == '#'){
                
$output .= " <span style='cursor:pointer !important; cursor:hand; color:blue'  title=\"$entry_row[DISPLAY_NAME]\" name=\"$entry_row[DISPLAY_NAME]\" ";
                
$output .= $entry_row['LINK'];
                
$output .=" >$entry_row[DISPLAY_NAME]</span>\n</a>\n</li> ";
            }else{
                
$output .= " <a href=\"$entry_row[LINK]\" name=\"$entry_row[DISPLAY_NAME]\"";
                
$output .= " title=\"$entry_row[DISPLAY_NAME]\">\n";
                
$output .= " <span>$entry_row[DISPLAY_NAME]</span>\n</a>\n</li> ";
            }
            
            
$output .= " \n";
        }
    }
    return 
$output;

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  #4  
Old September 24th, 2009, 12:56 AM
anitha anitha is offline
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thany you for your reply
I want different menu for different users like one for normal user the other for admin user how to get that
thanks in advance

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Old September 24th, 2009, 05:54 PM
icandothat's Avatar
icandothat icandothat is offline
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That is what the code above does. I actually left out one function and you would have to handle database connectivity yourself but basically you build the menu by querying the database to determine what menu items are visible to the roles of the current user.

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