
April 26th, 2002, 08:22 PM
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Join Date: Apr 2007
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PHP Script Help
Hi,
I was just testing an ADD/DELETE/EDIT script in PHP but i cant get the EDIT to work properly. I know what the problem is but im not sure how to fix it.
When EDIT is clicked on one of the names it uses the "WHERE ID=$ID" to get the information about that name. The problem is when SUBMIT is clicked, the ID is not passed along to the part of the script that edits the information in the database, so it doesnt know which record to edit.
All i need is a way of passing the ID through the form to the next part of the page so that it would work.
At the moment I have to put the ID Field in and it works (but i know its not a very good way of doing it) , the page is at http://members.lycos.co.uk/lukusoft...phpnametest.php and the code is below:
Code:
// ---------------------------------------------------EDIT---------------------------------------------------
// If user wants to edit a name
else if ($nav == "editname")
{
$resultIDedit = mysql_query("SELECT * FROM test WHERE ID=$ID", $linkID);
$rowedit = mysql_fetch_assoc($resultIDedit);
print "Edit data for<b> " . $rowedit[name] . " " . $rowedit[surname] . "</b>";
print "<form name=edit method=get action=phpnametest.php>";
print "<font face=Verdana size=2>ID:";
print "</font><font face=Arial, Helvetica, sans-serif size=2><br />";
print "<input type=text name=editnameID size=3 value=" . $rowedit[ID] . "><br />";
print "Name</font><font face=Arial, Helvetica, sans-serif size=2>:<br />";
print "<input type=text name=editforename size=40 value=" . $rowedit[name] . "><br />";
print "Surname</font><font face=Arial, Helvetica, sans-serif size=2>:<br />";
print "<input type=text name=editsurname size=40 value=" . $rowedit[surname] . "><br />";
print "<input type=submit name=editnamesubmit value=SUBMIT /></form></font>";
}
// If a new name is submitted, add it to the database
else if ($editnamesubmit == "SUBMIT")
{
$doeditname = "UPDATE test SET name='$editforename',surname='$editsurname' WHERE ID=$editnameID";
// Inform the user wether the edit was successful, and show the button to return
if (@mysql_query($doeditname))
{
print("<p>Success! The name has been changed</p></b>");
}
else {
print("<p>Error changing name: " .
mysql_error() . "</p>");
}
print "<p><a href='$PHP_SELF'>Return To Main Page</a></p>";
}
Thanks a lot
Luke
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