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Multi Column Output Problem

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  #1  
Old December 4th, 2003, 10:08 PM
nesbit nesbit is offline
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Multi Column Output Problem
Hi,

I have read the tutorial on the multi column output and i have it working great. I need to modify it slightly so i have multiple td's outputing per record. The layout i need is below.

<table border="1">
<tr>
<td>catimg1</td>
<td>catimg2</td>
<td>catimg3</td>
</tr>
<tr>
<td>catname1</td>
<td>catname2</td>
<td>catname3</td>
</tr>

and so on....


Here is my current php code from the multi col tutorial.

php Code:
Original - php Code 
  1.  
  2. for ($i = 0; $i < $numrows; $i++) {
  3.           $db_row = mysql_fetch_array($db_result);
  4.           if ($i % $columns == 0) {
  5.             // no remainder, start a new row
  6.             echo "<tr>n";
  7.           }
  8.           print ("<td>$db_row[category_name]</td>n");
  9.           
  10.           if (($i % $columns) == ($columns - 1) || ($i + 1) == $numrows) {
  11.             echo "</tr>n";
  12.           }
  13.       }



if anyone can help me out it would be greatly appreciated.
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  #2  
Old December 4th, 2003, 10:43 PM
wfactor wfactor is offline
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RE: Multi Column Output Problem
something like
php Code:
Original - php Code 
  1.  
  2. $cols = "3";
  3.  
  4. if(is_int($i/$cols)) 
  5.              { 
  6.                 echo "</tr><tr>";
  7.   }


basically if the result of the if statement is a full number, ie, 1, 2 instead of 1.2, 2.4 etc then it will echo the </tr><tr>
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  #3  
Old December 4th, 2003, 10:52 PM
nesbit nesbit is offline
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RE: Multi Column Output Problem
Just wondering if you could elaborate a bit more on the reply please?
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  #4  
Old December 5th, 2003, 03:25 AM
Matt Matt is offline
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RE: Multi Column Output Problem
This is untested, but should work:

php Code:
Original - php Code 
  1. for ($i = 0; $i < $numrows; $i++) {
  2.     $db_row = mysql_fetch_array($db_result);
  3.     if ($i % $columns == 0) {
  4.         // no remainder, start a new row
  5.         echo "<tr>n";
  6.         unset($td1, $td2, $td3); /*added*/
  7.     }
  8.     print ("<td>$db_row[category_image]</td>n"); /*changed to category_image*/
  9.     $td{$i % $columns + 1} = $db_row['category_name'];/*added*/
  10.     
  11.     if (($i % $columns) == ($columns - 1) || ($i + 1) == $numrows) {
  12.         echo "</tr>n<tr>";
  13.         echo "<td>$td1</td>n"; /*added*/
  14.         if(isset($td2)) echo "<td>$td2</td>n"; /*added*/
  15.         if(isset($td3)) echo "<td>$td3</td>n"; /*added*/
  16.         echo "</tr>n"; /*added*/
  17.     }
  18. }


Basically, this stores the next row of info in some temporary variables and then displays them when it is done displaying the current row....I've commented the code so you can see what I added...
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  #5  
Old December 5th, 2003, 03:27 AM
Matt Matt is offline
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RE: Multi Column Output Problem
One other thing...it is hard coded now to work for 3 columns...more or less columns will need adjustments to the code...
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